x(x+2)-(x+1) >10(x+2)
x2 + 2x -x -1 > 10x +20
x2 > 9x + 21
x2 -9x -21 >0
x=11 gives 121 -99 -21 = 1 Eleven is the first x value to be >0
try 11 12 and 13
11(13)-12 >10(13)
143-12>130
131>130 and yes! the numbers are 11 12 and 13
24. The second is 26.
The 3 consecutive odd positive integers are 7, 9 and 11.
First, we are not interested for the sign of the numbers, because the product of two negative numbers is always positive, so we need to find the two consecutive factors of 240, which are 15 and 16. Thus, the numbers are -16 and -15.
The sum of the first four non-negative, consecutive, even integers is 20.
The let statement is: let the smallest of the three integers be x.
10-11-12
24. The second is 26.
The 3 consecutive odd positive integers are 7, 9 and 11.
First, we are not interested for the sign of the numbers, because the product of two negative numbers is always positive, so we need to find the two consecutive factors of 240, which are 15 and 16. Thus, the numbers are -16 and -15.
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
The sum of the first four non-negative, consecutive, even integers is 20.
The let statement is: let the smallest of the three integers be x.
-7
The first integer is 17.
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
18, 20 and 22