Math and Arithmetic

Top Answer

There are no two consecutive even integers, consecutive odd integers,

or consecutive integers that satisfy that relationship.

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0No two consecutive integers can add up to 98.No three consecutive integers can add up to 98.But 23, 24, 25, and 26 can.

27,28,29The sum of which is 84.

There is no set of three consecutive integers for 187.

There is no set of three consecutive integers for 106.

9240 is the product of the three consecutive integers 20, 21, and 22.

There is no set of three consecutive integers whose sum is 71.

There is no set of three consecutive integers whose sum is 88.

The sum of three consecutive integers is -72

The sum of the squares of the three consecutive integers 11, 13, 15 = 515

Does not exist. -------------------------------------------------------------------------------------------------------------- Whoever wrote this answer is as dum as a nut wastes excretion.

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).

find three consecutive integers whose sum is - 93

There are no three consecutive odd integers who's sum equals 13.

The three integers are 187, 188 and 189.

Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.

20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22

No. There is no set of three consecutive even integers with a sum of 40.

this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6

Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.

The integers are -1, 1 and 3.

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.

The three integers are 25, 26, and 27.

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.

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