The sum of the squares of two consecutive positive even integers is 340. Find the integers.
12 and 14.
122 + 142 = 340
The product of 2 consecutive positive number is 48. Find the 2 numbers
There is no solution.Consecutive negative integers will always add up to a negative number. 110 is positive.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
spelling is correct
The numbers are 65 and 67.
42 + 52 = 16 + 25 = 41
The integers are 5 and 7.
count the top row of squares and multiply that by the number of squares in a coloumn ( which are going down )
If you have two consecutive integers then one of them must be odd and the other must be even. The square of an odd integer must be odd, the square of an even integer must be even. The sum of an odd number and an even number must be odd. Thus, the sum of squares of any two consecutive numbers must be odd. Therefore, the question has no valid answer.
5 & 7 (25 + 49)
169 = 144 + 25, so your numbers are 12 & 5.
In the classic puzzle with squares of differeing sizes within squares, the number is 40.Its a popular net puzzle.
The negative part is just a trick because any number squared, whether positive or negative, will turn out to be a positive number. But, to satisfy the question... -6*-6=36 -8*-8=64 36+64=100 tada. -6 and -8 would be the answer.
The 3 consecutive odd positive integers are 7, 9 and 11.
5 and 7 52+72 = 74
4, 5 & 6 (16 + 25 + 36)
The numbers are 8 and 9.
Ans - 7and 8
99 = 9*11
No. Every third consecutive natural number is divisible by 3.
to find the difference between a negative number and a positive number, you do the same thing as you would do for a positive and positive number. You just subtract the smaller number (which would of course be the negative) from the larger number (the positive). example: difference between 7 and -4 7 - (-4) = 11