A couple.
Three One is obviously out. Two is out because if two unequal forces n and p act on an object the resultant with the minimum force in magnitude is |n - p|, which will never be 0 if n =/= p. Three can be easily resolved with a quick example. Imagine an object with three concurrent forces acting on it. Two forces, n = 3 N and p = 4 N, create an angle with each other such that the resultant is 5 N. 180 degrees from the resultant, a force, r = 5 N, is acting on the object. Thus three unequal vectors on an object can result in 0.
No.
The only way that two vectors add up to zero is if they have equal magnitude and opposite direction. If the magnitudes are not equal then no, they cannot give a zero resultant.
Assuming you want non-zero vectors, two opposing vectors will give a resultant of zero.
Yes if you put them "head to tail" and the head of the fourth one points to the tail of the first one the resultant is zero.
forces in the same direction can be added to give us the resultant force and opposite force will subtracted to get resultant force
Force is a vector. So only depending on the direction of the forces we can give the resultant.
A couple is a mechanical term defined as a system of forces that produces a resultant moment but not a resultant force. The moment caused by a couple is different than the moment caused by a single force. The moment of a force is dependent upon a reference point (i.e. if this reference point changes the moment also changes), therefore it is a fixed (or bound) vector. However, the moment (or torque) of a couple is independent of a reference point. In other words any reference point will give the same torque. This fact is proven in Varignon's Second Moment Thereom. Since the moment (or torque) of a couple is independent of a reference point, it may be represented as a free vector. This means that the vector may be freely moved in space.
Torque= length x force. Lenght is the distance to an object. Force must be perpendicularly acting on the object. In your question, you did not specify neither force and length of the knob. So I cannot give you a torque value. I believe the SI unit for torque is "Nm", assuming that you calculated your torque using all SI units. Then you have to convert Nm to pounds.
The way torque works, these two cases give the same torque, or twisting force, to the object at the pivot point. To find the torque applied, multiply the force by the distance. Obviously this is the same in the two cases you describe.
No. The tenth vector would have to be matched by one equal and opposite vector to yield a zero resultant, or by multiple vectors in the second plain collectively yielding a zero resultant for that plane. It would be possible, for example, for 8 vectors to be on the same plane and two on a different plane to give a zero resultant.
In that case, the forces are said to be unbalanced.
Interpreting the question as follows... "When is an object in equilibrium according to its component forces?"When all component forces cancel leaving no resultant force.For example - If Joe pulls on a crate with a force of 10 Newtons North, and Sally pulls on the same crate at the same time with a force of 10 Newtons South then all of the component forces combine to give a resultant force of zero. Thus the crate is in equilibrium. Math: 10 + (-10) = 0
Three One is obviously out. Two is out because if two unequal forces n and p act on an object the resultant with the minimum force in magnitude is |n - p|, which will never be 0 if n =/= p. Three can be easily resolved with a quick example. Imagine an object with three concurrent forces acting on it. Two forces, n = 3 N and p = 4 N, create an angle with each other such that the resultant is 5 N. 180 degrees from the resultant, a force, r = 5 N, is acting on the object. Thus three unequal vectors on an object can result in 0.
The pelvic Thrust
*falls* Ow.
Avalanche