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Given that 3x-ax-2x-73x3-32x2 87x-70 determine the value of a?
Wiki User
∙ 16y ago
3x-ax-2x-73x3-32x2=87x-70 First change to addition so it is easier to simplify 3x+(-ax)+(-2x)+(-73x3)+(-32x2)=87x-70 Combine all of the like terms x+(-ax)+(-73x3)+(-32x2)=87x-70 get rid of the x on the left side -ax+(-73x3)+(-32x2)=86x-70 Now you can move the 73x3 and the 32x2 to the other side by adding it to both sides to get rid of the first because they are negative. -ax=86x-70+73x3+32x2 now divide both sides by -x to get a by itself and positive. a=(86x-70+73x3+32x2)
.... -------------------------
...................-x
(Ignore the dots, they wont let me space without getting rid of the spaces after I post it) Then you can use distributive property on the fraction. a=-86-(70/-x)+(73x3/-x)+(32x2/-x)
Now I'm stuck, sorry, but can somebody else take over please?
Wiki User
∙ 16y ago
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