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(x + y)/2
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Wiki User
∙ 12y ago
Anonymous
i dontb know tell me the answer
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What is the algebraic expression for the one half the sum of x and y?
1/2 (x+y)
Twice the sum of x and y and The sum of twice x and y?
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
The sum of twice x and y?
2(x+y)=2x+2y
What is the product of 3 and x divided by the sum of x and y?
3x over x + y
Which expression correctly describes x divided by the sum of y and 7?
X/(y+7)
What is the algebraic expression for the one half the sum of x and y?
1/2 (x+y)
Twice the sum of x and y and The sum of twice x and y?
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
What is the difference between twice the sum of x and y and the sum of twice x and y?
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
The sum of x and y decreased by their product?
The sum of x and y decreased by their product is (x + y)- xy.
The sum of x and y?
x+y
How do you write the sum of x and y?
X+y
What is the answer to 9 Times the sum of x squared and y decreased by 4 times the sum x squared and y?
5(x^2 + y)
The sum of two number is 10 and their product is 30 the sum of their reciprocals is?
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
If the sum of two numbers is 7 and there product is 25 what is the sum of there reciprocals?
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
How can a difference be written as a sum in math?
x - y = x + (-y)
The sum of twice x and y?
2(x+y)=2x+2y
What are the sum and difference identities for the sine cosine and tangent functions?
Sine sum identity: sin (x + y) = (sin x)(cos y) + (cos x)(sin y)Sine difference identity: sin (x - y) = (sin x)(cos y) - (cos x)(sin y)Cosine sum identity: cos (x + y) = (cos x)(cos y) - (sin x)(sin y)Cosine difference identity: cos (x - y) = (cos x)(cos y) + (sin x)(sin y)Tangent sum identity: tan (x + y) = [(tan x) + (tan y)]/[1 - (tan x)(tan y)]Tangent difference identity: tan (x - y) = [(tan x) - (tan y)]/[1 + (tan x)(tan y)]
