Cutting the equilateral triangle in half results in two right triangles each with a base of length x/2, and angles of 30, 60, and 90 degrees. Using the lengths of sides of a 30-60-90 triangle it can be found that the height is (x/2)√(3), which is the same as the height of the equilateral triangle.So the height of the equilateral triangle is x√(3) / 2.
30 square inches. Area of triangle = (base x height) divided by 2.
Area of Triangle = 1/2 base x height 28 = 4 x height height = 7 cms
area of a triangle = (base x height)/2 = (4 units x 14 units)/2 =28 square units
The area of a triangle = base/2 x height
Area of triangle = 1/2 x base x height 17.5 = 1/2 x 7 x height 17.5 = 3.5 x height height = 17.5 /3.5 = 5 meters
Remember that in a triangle: (Base x Height) / 2 = Area In your question: (4 x Height) / 2 = 16 Now just solve for Height: (4 x Height) = 16 x 2 = 32 Height = 32 / 4 = 8 So your answer is 8 units.
area of any triangle is 1/2 x base x height.
Area of a triangle = (1/2) x (base) x (height) Can you handle it from there ?
With a 30 deqree angle at the top of a triangle and a height of 15
Area of a triangle = 1/2 x base x altitude(height)On putting given values, we get45cm2 = 1/2 x 6cm x height(altitude)cm45 = 3 x altitudealtitude = 15 cmAnswer to the question is 15cm.
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.