the roots are 1, - 1/3, - 3 1/2 and 3 1/2
No. The square roots of 2, 3 and 5, for a start, are not rational.
No, they are not.
Rational roots
Yes. Both square roots of 36 are rational.
No, the vast majority are not.
In algebra, the rational root theorem (or rational root test, rational zero theorem or rational zero test) states a constraint on rational solutions (or roots) of a polynomialequationwith integer coefficients.If a0 and an are nonzero, then each rational solution x, when written as a fraction x = p/q in lowest terms (i.e., the greatest common divisor of p and q is 1), satisfiesp is an integer factor of the constant term a0, andq is an integer factor of the leading coefficient an.The rational root theorem is a special case (for a single linear factor) of Gauss's lemmaon the factorization of polynomials. The integral root theorem is a special case of the rational root theorem if the leading coefficient an = 1.
Rational zero test cannot be used to find irrational roots as well as rational roots.
-39 has no rational roots.
No. Lots of square roots are not rational. Only the square roots of perfect square numbers are rational. So for example, the square root of 2 is not rational and the square root of 4 is rational.
A rational expression is not defined whenever the denominator of the expression equals zero. These will be the roots or zeros of the denominator.
The square roots are irrational.
No. The square roots of 2, 3 and 5, for a start, are not rational.
The square root of 16 is rational. The answer would be 4, so, yes; they can be rational.
The square roots are rational.
I do not believe that there are any rational roots.
Some square roots are rational but the majority are not.
They are rational because the characteristic of evenness and unevenness is relevant only in the context of integers. And all integers are rational.