Go through each of the numbers, and count how many of them are odd. If you count an odd number of them, then their sum is odd. If you count an even number of them, then their sum is even.
Add them up and divide the sum by 2.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
even numbers
numbers! An endless string or 'series' of even numbers!
That is not possible; adding two even numbers always gives an even number
Add them up and divide the sum by 2.
Yes it is possible to determine if a product will be even or odd. To do this, we need to consider what an even number is. Even numbers are numbers with at least one factor of 2 (meaning they are divisible by 2). Thus, any product of numbers which contains at least one even number will result in an even product. If all of the numbers being multiplied together are odd, the product will be odd. If one or more of the numbers is even, the product will be even.
If at least one of the numbers is even, the result will be even. Otherwise all the numbers are odd and the result will be odd.
Yes, all you have to do is to count the number of ODD numbers in the list. If it is odd, then the sum will be odd; if even, so will the sum. Knowing this can help you run a quick validity check when you sum up a list of numbers. (The method works because: a) the sum of two even numbers is even, and b) the sum pf two odd numbers is even, but c) the sum of an even number and an odd number is odd. Hence, if you only determine whether there are any unpaired odd numbers, you know the answer.)
Type your answer here... Dertermine three consecutive even numbers who's sum is 42?
You can't. Only whole numbers are odd or even.
if there is an od quantity of odd numbers the sum will be odd....example 1 3 4 6 has two odds so it will be even =14 1 3 5 6 has three odds and it is = 15
Just add the end numbers, so 3 + 5 + 4 + 7 = 19 which is odd. Alternatively, ignore even numbers [such as 4], and two odd numbers [3 and 5] added always make an even number [8], which leaves and odd number [7] so the answer will be odd. Example; five hundred different numbers, where 483 are even and 17 are odd, then no matter what the actual 500 numbers are the answer will be odd, as there is an odd [17] quantity of odd numbers.
It doesn't matter what the first number is. All that matters is the ones place to determine if the number is odd or even.
The parity rules are: Odd + Odd = Even Even + Even = Even Odd + Even = Odd Even + Odd = Odd So the parity where one number is even is that of the other number. This means that you can go through a list of numbers and ignore all the even numbers. Every PAIR of odd numbers has even parity and by the previous paragraph, even parity can be ignored. So you can pair off odd numbers and ignore them.
All even numbers are composite except 2 itself which is a prime number because it has only two factors which are itself and one.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.