if there is an od quantity of odd numbers the sum will be odd....example
1 3 4 6 has two odds so it will be even =14
1 3 5 6 has three odds and it is = 15
Even plus even equals even. Odd plus odd equals odd. Odd plus even equals odd. 13 + 45 (odd plus odd) will be even. Even plus 24 will be even. Even plus 17will be odd. 13 + 45 + 24 + 17 will be odd.
If at least one of the numbers is even, the result will be even. Otherwise all the numbers are odd and the result will be odd.
If the factorization includes the number 2, it's even. If not, it's odd.
Even. There are several ways to determine whether an integer is even or odd, all of which indicate that 0 is an even number: it is a multiple of 2, it is evenly divisible by 2, it is surrounded on both sides by odd integers, and it is the sum of an integer with itself. See related links for detailed proof.
You have to look at the ones place digit for the quick way to this. If both ones digits are even then it will be even, if they are both odd then it will be even, if one is odd and one is even then it will be odd.
Add them up and divide the sum by 2.
To determine whether a given number is odd or even: function odd_even($i) { return ($i % 2 == 0 ? 'even' : 'odd'); }
Even plus even equals even. Odd plus odd equals odd. Odd plus even equals odd. 13 + 45 (odd plus odd) will be even. Even plus 24 will be even. Even plus 17will be odd. 13 + 45 + 24 + 17 will be odd.
If at least one of the numbers is even, the result will be even. Otherwise all the numbers are odd and the result will be odd.
If the factorization includes the number 2, it's even. If not, it's odd.
Even. There are several ways to determine whether an integer is even or odd, all of which indicate that 0 is an even number: it is a multiple of 2, it is evenly divisible by 2, it is surrounded on both sides by odd integers, and it is the sum of an integer with itself. See related links for detailed proof.
You have to look at the ones place digit for the quick way to this. If both ones digits are even then it will be even, if they are both odd then it will be even, if one is odd and one is even then it will be odd.
Go through each of the numbers, and count how many of them are odd. If you count an odd number of them, then their sum is odd. If you count an even number of them, then their sum is even.
Yes, all you have to do is to count the number of ODD numbers in the list. If it is odd, then the sum will be odd; if even, so will the sum. Knowing this can help you run a quick validity check when you sum up a list of numbers. (The method works because: a) the sum of two even numbers is even, and b) the sum pf two odd numbers is even, but c) the sum of an even number and an odd number is odd. Hence, if you only determine whether there are any unpaired odd numbers, you know the answer.)
The parity rules are: Odd + Odd = Even Even + Even = Even Odd + Even = Odd Even + Odd = Odd So the parity where one number is even is that of the other number. This means that you can go through a list of numbers and ignore all the even numbers. Every PAIR of odd numbers has even parity and by the previous paragraph, even parity can be ignored. So you can pair off odd numbers and ignore them.
Very easily: if the prime factorization includes 2, it's even. If not, it's odd.
Just add the end numbers, so 3 + 5 + 4 + 7 = 19 which is odd. Alternatively, ignore even numbers [such as 4], and two odd numbers [3 and 5] added always make an even number [8], which leaves and odd number [7] so the answer will be odd. Example; five hundred different numbers, where 483 are even and 17 are odd, then no matter what the actual 500 numbers are the answer will be odd, as there is an odd [17] quantity of odd numbers.