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If you have two numbers, multiply them together and divide that total by the GCF. The result will be the LCM.

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Q: How can you find the LCM of a set of a numbers given their greatest common factor without listing the multiples of the numbers?
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Which number can divided by 3 without leaving a remainder?

The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three.


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Without a specific number, all of the numbers in that range are multiples.


List the integers from 1 to 20 inclusive that are multiples what numbers?

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Which numbers below have 2 and 4 factor?

Difficult to answer without knowing the numbers below. Choose multiples of 4. They will be even numbers.


How do you write a C program using an integer array to print array numbers up to 100 and then remove all numbers that are divisible by 2 and print out the remaining numbers and continue for 3 to 9?

#include<stdio.h> #include<conio.h> void main() { int i, a[100]; clrscr(); printf("Numbers from 1 to 100"); for(i=1;i<=100;i++) printf(" %d",a[i]); printf("Numbers from 1 to 100 without multiples of 2"); for(i=1;i<=100;i++) { if (a[i]%2 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 3"); for(i=1;i<=100;i++) { if (a[i]%3 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 4"); for(i=1;i<=100;i++) { if (a[i]%4 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 5"); for(i=1;i<=100;i++) { if (a[i]%5 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 6"); for(i=1;i<=100;i++) { if (a[i]%6 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 7"); for(i=1;i<=100;i++) { if (a[i]%7 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 8"); for(i=1;i<=100;i++) { if (a[i]%8 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 9"); for(i=1;i<=100;i++) { if (a[i]%9 !=0) printf(" %d",a[i]); } getch(); }


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This will be difficult to answer accurately without knowing each set of numbers.


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