Suppose A is the first term and R is common difference.
Then, if t(n) is the nth term,
t(n) = A + n*R
Then
t(5) = A + 5R
and
t(3) = A + 3R
so that
t(5) - t(3) = 2R
Now t(1) = A + R = A + 3R - 2R (since R = 3R - 2R)
So t(1) = t(3) - 2R
You were given t(3) and have calculated 2R above, so can work out t(1).
That's an arithmetic sequence.
No. An 'arithmetic' sequence is defined as one with a common difference.A sequence with a common ratio is a geometricone.
The nth term of an arithmetic sequence = a + [(n - 1) X d]
The sequence is arithmetic if the difference between every two consecutive terms is always the same.
An arithmetic sequence.
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
That's an arithmetic sequence.
arithmetic sequence
No, the Fibonacci sequence is not an arithmetic because the difference between consecutive terms is not constant
No. An 'arithmetic' sequence is defined as one with a common difference.A sequence with a common ratio is a geometricone.
The nth term of an arithmetic sequence = a + [(n - 1) X d]
The sequence is arithmetic if the difference between every two consecutive terms is always the same.
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Arithmetic Sequence
An arithmetic sequence.
arithmetic sequence this is wrong
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