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By Pythagoras

x2+ 92= 142

So x2= 142- 92= 196 - 81 = 115

therefore = x = sqrt(115) = 10.7 (approximately).



By Pythagoras

x2+ 92= 142

So x2= 142- 92= 196 - 81 = 115

therefore = x = sqrt(115) = 10.7 (approximately).



By Pythagoras

x2+ 92= 142

So x2= 142- 92= 196 - 81 = 115

therefore = x = sqrt(115) = 10.7 (approximately).



By Pythagoras

x2+ 92= 142

So x2= 142- 92= 196 - 81 = 115

therefore = x = sqrt(115) = 10.7 (approximately).

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βˆ™ 11y ago
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Wiki User

βˆ™ 11y ago

By Pythagoras

x2+ 92= 142

So x2= 142- 92= 196 - 81 = 115

therefore = x = sqrt(115) = 10.7 (approximately).

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Q: How can you find the missing measure of the right leg of a 14x9 cm right triangle to the nearest tenth using the Pythagorean property?
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