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Q: How can you get coefficients that are equal for y. 3x plus 5y equals 7 2x plus 15y equals 11?

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i have no clue what the answer is

x/5y + 2x/3y = 3x/15y + 10x/15y = 13x/15y

what is the slope-intercept form of the equation 15y=10x+12

15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5

.225

3y plus 6x = 2

No.

Combine like terms, meaning add 12X plus 4X which is 16X and then you add 25Y plus 15Y which equals 40Y so the answer will be 16x+40y. combine like terms means add the ones with the same variable.

If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656

5

Y=55y-3=2y+123y-3=123y=15y=5

3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20

10y=15y=1.5

The slope is 1/3 and the y-intercept is -1.

(2x + 3y)(2x + 5y)

5(x + 2 + 3y)

Multiply first equation by 3: 9x + 15y = 63Add that and second equation: 19y = 57Divide by 19: y = 3, so x = 2

Yes because you have a letter in there that represents a number.

2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12

5x-15y = -10

15y-15=0,y=1

15 y + 20 = 5(3y + 4)

GCF(15y, 25) = 5.

A: 11x = 5y + 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 3x - 5y = 40 A - B: 8x = 40 x = 5 Now we can plug that value of x into one of the original equations to solve for y: 11(5) - 5y = 80 55 - 5y = 80 -5y = 25 y = -5