Find factors of 8 that add up to 6.
(x + 2)(x + 4)
x2 + 6x + 8 =(x + 2)(x +4)
We know that when you submit questions you aren't free to use the right format to make the mathematical terms crystal clear. It is likely that you mean "x squared times 6 plus x squared times 2", which is clearer. You can factor out the "x squared" and you will see that you get "x squared times 8". You COULD mean (6x) squared plus (2x) squared, which would be different. 6x times 6x would equal x squared times 36, so your answer will be much different.
2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i
(X + 2)(X + 4) Factored
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
x2 + 6x + 8 =(x + 2)(x +4)
5x(6x + 7y + 8)
the answer is (3x-2)(9x squared+6x+4)
(x^2 - 2)(x - 2)(x + 2)
We know that when you submit questions you aren't free to use the right format to make the mathematical terms crystal clear. It is likely that you mean "x squared times 6 plus x squared times 2", which is clearer. You can factor out the "x squared" and you will see that you get "x squared times 8". You COULD mean (6x) squared plus (2x) squared, which would be different. 6x times 6x would equal x squared times 36, so your answer will be much different.
It is: 3x2+6x-11 = 0
x2 + 6x + 8 = (x + 4)(x + 2)
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
8(6x+1)
-((x + 2)(x - 8))
It is: (2x+3)(3x-8) when factored
2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i