Best Answer

You don't.

Furthermore, how would you prove your not a virgin? Either way your fu'd.

Improved Answer:-

y = x+k

x2+y2 = 4

Substitute y = x+k into the bottom equation:

x2+(x+k)(x+k) = 4

x2+x2+2kx+k2 = 4

k2 = 8 so therefore:

2x2+2kx+8-4 = 0 => 2x2+2kx+4 = 0

For the straight line to be a tangent to the curve the discriminant b2-4ac of the quadratic equation must equal zero:

Hence:-

(2*k)2-4*2*4 = 0

k2 = 8

So: 4*8-4*2*4 = 0 => 32-32 = 0

Therefore the straight line y = x+k is a tangent to the curve x2+y2 = 4

Q: How can you prove that the straight line of y equals x plus k is a tangent to the curve of x squared plus y squared equals 4 and only when k squared equals 8?

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2

k = 0.1

If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2

Tangent to the curve.

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k = 0.1

It is (-0.3, 0.1)

If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2

Tangent to the curve.

If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.

In geometry a straight line that touches a curve is called a tangent.

Tangent:In geometry, the tangent line (or simply the tangent) is a curve at a given point and is the straight line that "just touches" the curve at that point. As it passes through the point where the tangent line and the curve meet the tangent line is "going in the same direction" as the curve, and in this sense it is the best straight-line approximation to the curve at that point.Chord:A chord of a curve is a geometric line segment whose endpoints both lie on the outside of the circle.

A tangent is a line that just touches a curve at a single point and its gradient equals the rate of change of the curve at that point.

A tangent line touches a curve or the circumference of a circle at just one point.

A tangent line.