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Q: How can you solve this equation ax plus ax2-bx-bx2?

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Co variable

Ax + By + Cz + D = 0

The expression you presented is not an equation. Do you mean ax2 + bx = c? Do you mean to solve it for x? I'm assuming that's the case, but you need to be more clear on your question. To solve for x then, the technique to use is called completing the square: ax2 + bx = c Multiply both sides by a: a2x2 + abx = ac Add the square of b/2 to both sides: a2x2 + abx + (b/2)2 = ac + (b/2)2 We now have a perfect square on the left, simplify: (ax + b/2)2 = ac + b2 / 4 (ax + b/2)2 = (4ac + b2) / 4 And now solve for x: ax + b/2 = ±[(4ac + b2) / 4]1/2 ax + b/2 = ± √(4ac + b2) / 2 ax = [-b ± √(4ac + b2)] / 2 x = [-b ± √(4ac + b2)] / 2a

ax = b where a and b are given and a is not zero.

a(x + y - z)

Related questions

AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.

Co variable

ax - b = c ax = b + c x = (b + c)/a

A linear equation.

Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.

y = (c - Ax) / (B)

It is -a/b

a function

Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A

A linear equation ?

I believe its coefficient.

x = (d-a)/(a-c)

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