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Q: How can you use 2 6's and 3 2s to make 50?

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5 and 1/2's, 6s, 6 1/2s, 7s, and 7 1/2s

14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3

6s+2s=72 combine like terms 6s+2s=8s set equal to 72 8s=72 divide both sides by 8 to solve for "s". 8s=72 8 8 your answer is s= 72/8 which is 9.

9r2-4s2/9r+6sIt looks like you can factors the numerator(3r + 2s)(3r - 2s) [This is the factored form of 9r2-4s2]Put this back into the equation(3r+2s)(3r-2s)/9r+6sYou can also factor the denominator3(3r+2s)Put this back into the equation(3r+2s)(3r-2s)/3(3r+2s)You can cancel out the 3r+2s on top and bottom because they are the same they equal 1. Therefore your final answer is3r-2s over 3You could go further and say this is...r-(2/3)seither one is correct

50

It is from -50 to 70

Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)

As it is written, it makes no sense. If you mean: (s)(3t)(2s-2t) then the answer is 6s^2t - 6st^2 or (6st)(s-t) If the statement is something else, then the answer is something else

50

Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0

A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s

8 if them with a remainder of 2

To reset the index

1s-2s-2p-3s-3p-3d-4s-4p-4d-4f-5s-5p-5d-5f-6s-6p-6d-7s

1s, 2s, 2p,3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d

It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0

Both hands are full houses, which means that there is a three of a kind and a pair in each hand. When comparing these hands the three of a kind is what determines the winner, in this case three 6's beats three deuces.

61

1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p

6/6 +6/6=2

66-66+66= 66

-40 = 8-6s -40 - 8 = 6s -48 = 6s 8 = s

36 playing cards in a Russian deck. Russian deck starts with 6s. There are same four suits as American deck but 2s, 3s, 4s and 5s are missing.

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, and 7p

6 and 6/6 = 7