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Q: How do describe a rectangle with whole number dimensions that has the greatest perimeter for a fixed area?

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21 x 2 has greatest perimeter

The greatest area that a rectangle can have is, in fact, attained when it is a square. A square with perimeter of 16 cm must have sides of 4 cm and so an area of 4*4 = 16 cm2.

The greatest area for a fixed perimeter will be when all the sides are equal or when the rectangle approaches the shape of a square.

In whole numbers, the greatest perimeter would be a rectangle 48 x 1, resulting in a perimeter of 98m.

The square is.

90.25 ft2

The greatest area is 10000 square yards.

It's greatest possible perimeter: 1+39+1+39 = 80 feet

12+12=24

42 square units.

81 square feet.

42.25 cm2

It is 182 cm.

12.25 sq metres.

For any given area, the rectangle closest to a square will have the smallest perimeter; and the one that is most "stretched out" has the largest perimeter. In this case, that would be a width of 1 and a length of 2014.

This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.

If it's allowed to be a square, 625 square feet. If not, 624 square feet.

Because area is a function of perimeter.

The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.

Circle, square, triangle and rectangle of same perimeter. Which will have more area?? The circle will have the greatest area. For regular polygons, the greater the number of vertices, the greater the area. (And so, in the limit, the circle, with an infinite number of vetices, has the greatest area.)

For any perimeter, the rectangle with the greatest area is a square.For a 16-inch perimeter, the greatest rectangular area is 16 square inches,inside a square with 4-inch sides.But if you don't necessarily need straight sides, then you can squeeze more areainside the same perimeter with a circle. A circle with a 16-inch circumference has anarea of 20.372 square inches.

t2 ÷ (2( π + 4) π = pi

The greatest possible area of a rectangle is simply the area of a square, which is a special type of rectangle.in order to find the area of that square:4s=96 (4s=4 sides)s=24A=lwA=24*24A=576so the area of that rectangle would be 576 ft...

The greatest area is attained when the rectangle is, in fact, a square. Then it has sides of 5 cm and an area of 25 cm2. If you are not permitted to have a square then the answer is as close to 25 cm2 as you can get without actually getting there. So, more than 24.99, more than 24.99999 etc but never quite 25.

The rectangle.