Q: How do get 115 with 12 5 3 4 10?

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3/10 and 4/12 can both be converted in 60ths.3/10 becomes 18/604/12 becomes 20/60So it is then clear that 4/12 is bigger than 3/10

(10/12) - (1/4) = (10/12) - (3/12) = 7/12

12 / 4 = 3 40 / 4 = 10 Answer being: 3 over 10 (3/10)

1/4 = 3/12 So 10 1/4 = 10 3/12 = 123/12

3/4

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A decagon has 10 sides, a dodecagon 12, and a pentagon 5. So 4 decagons, 5 dodecagons, and 3 pentagons have 4*10 + 5*12 + 3*5 sides = 40 + 60 + 15 = 115 sides altogether.

3/10 and 4/12 can both be converted in 60ths.3/10 becomes 18/604/12 becomes 20/60So it is then clear that 4/12 is bigger than 3/10

(10/12) - (1/4) = (10/12) - (3/12) = 7/12

7-10 = -3 4 x 3 = 12 12 + -3 = 9

2/3 + 3/4 + 10/12 = 8/12 + 9/12 + 10/12 = 27/12 = 2 & 3/12 = 2 & 1/4

12 / 4 = 3 40 / 4 = 10 Answer being: 3 over 10 (3/10)

1/4 = 3/12 So 10 1/4 = 10 3/12 = 123/12

3/4

If 4*y + 10 = 22Then 4*y = 12 (because 22 -10 = 12)Then y = 3 (because 4*3 =12)

115 ÷ 4 = 28 with remainder 3

4/12 + 10/12 - 3/12 = 11/12

12/40 factor 4*3/4*10 eliminate 4; top and bottom 3/10