X (x - 25) So X = 0 Or X = +25
This is a quadratic equation in the form of: 52 - 25x + 30 = 0 Solve by using the quadratic equation formula: x = 2 or x = 3 Or by factorising: (5x-10)(x-3) = 0, which means that x = 10/5 or x = 3
Using algebra to solve this problem (12 + .25x = 30), the answer (x) is 72.
25x + 75 = 25*(x + 3)
25x = 11 so x = 0.44
25x-32 = 7 25x-9 = 7 25x = 7+9 25x = 16 x = 16/25
X (x - 25) So X = 0 Or X = +25
5y=25x 25x=5y -5y 25x-5y=0
This is a quadratic equation in the form of: 52 - 25x + 30 = 0 Solve by using the quadratic equation formula: x = 2 or x = 3 Or by factorising: (5x-10)(x-3) = 0, which means that x = 10/5 or x = 3
Using algebra to solve this problem (12 + .25x = 30), the answer (x) is 72.
25x + 75 = 25*(x + 3)
25x = 11 so x = 0.44
The answer is all the points on the line defined by 25x - 12y = 1
.25x+3=10 .25x=7 25x=700 x=28
The total magnification would be 10x (ocular lens) multiplied by 25x (objective lens), which equals 250x magnification.
25x (square) plus 40 plus 15 equals 680.
150=25x. so you have to isolate the variable, x, by doing the opposite operation of multiplication, which is division. Divide 25 by 25, you cancel out, making you divide 150 by 25, your answer being 7. You could also count like quarters, 25 cents each.