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Q: How do you Solve 6 over 7 subtract 1 over 8?

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1/3

1/6

No. (5/6) - (1/6) = 4/6 = 2/3

4/7 minus 1/6 = 17/42

6/9 - 1/3 = 2/3 - 1/3 = 1/3

It is: 7/12

18

First, subtract 1 from 6 turning your next component of the equation to be 5. Then add 5 and 6 to equal 11. Therefore, 6 - 1 + 6 equals 11.

It will be 1/6 because 31/6 minus 1/6 = 5

The answer is 1/6.

6 and 1/6

1/4

8 1/6 - 2 5/6 = 5 1/3. Here's how I did it. Borrow a 1 from the 8 and change it to 6/6 & add to 1/6, so you have 7 and 7/6. Subtract 5/6 from 7/6 = 2/6, which equals 1/3. Subtract 2 from 7 = 5.

37/6 minus 1/6 = 6

5/6 - 3/6 = 2/6 which simplifies to 1/3

(6/12) - (1/3) = (6/12) - (4/12) = 2/12 = 1/6

1

7/8 - 6/8 = 1/8

-5

x=1, y=1

4 over 1 is 4. 2 + 4 is 6.

So your equation is 3/x + 1/2 = 1/3 right? First, you have to subtract 1/2 from both sides. 1/3 and 1/2 have to have the same denominator to be added or subtracted, so 1/3 becomes 2/6 and 1/2 becomes 3/6. 2/6 - 3/6 = -1/6 . Now you have 3/x = -1/6. Cross multiply and you get 18 = -x. Therefore, x = -18. Hope that helps

3/4 minus 1/6 is 7/12

13/15 − 4/6 = 18/90 which reduces to 1/5

1/6=x/12 12=6x 2=x