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10 consecutive even numbers can be arranged in pairs of U1-U10, U2-U9, U3-U8, U4-U7 and U5-U6. Each pair MUST add to the same amount.

[U1-U10 must be the same as U2-U9 because U2 is two more than U1 while U9 is two less than U10]

So each pair must be 70/5 = 14

Now U10 = U1 + 2*9 = U1 + 18

So U1 + (U1 + 18) = 14

ie 2*U1 = -4 or U1 = -2

So the numbers are -2, 0, 2, 4, ... , 16

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Q: How do you add a set of 10 even consecutive numbers to get 70?
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