Aluminium and sulphur make aluminum sulfidebalanced equation: 16Al + 3S8 -> 8Al2S3
There is one type of metal in Al2S3 and that is Al (aluminum). If you want to know how many metal atoms are in 1 molecule of Al2S3, then the answer would be 2, because there are 2 Al atoms.
4 Al + 3O2 = 2Al2O3
Since aluminum cations are trivalent and sulfide anions are divalent, the formula is Al2S3, so that the charges balance.
Al and S combine to form aluminum sulfide, Al2S3
The oxidation number of Al is +III and S is -II.
2 al^3+ 3s^2-
Al2S3. Obviously, the 2 and 3 are subscript. The reason this happens is because of the bonding ratio: there are 3 S ions required to balance 2 Al ions.
Al + O2 will never yield Fe2O3.
Al and AgNO3. Al has a 3plus charge plus 3e negative. 3(Ag positive plus le negative equals Ag). Al plus 3Ag plus is equal to Al with a 3 plus charge plus 3Ag.
Al2S3 Name: Aluminum sulfide
S has an oxidation number of -2. Al is +3.
it is already balanced
4Al + 3O2 --------> 2Al2O3
Alumniniu sulfide react with water; it is not a dissolution.The reaction is:Al2S3 + 6 H2O = 2 Al(OH)3 + 3 H2S
In Al2S3 , there are 2 atoms of Al and 3 atoms of S. Aluminum is a metal, while Sulfur is a non-metal. So, there are 2 metal atoms.
The correct stoichiometric equation for the reaction of ammonium hydroxide and aluminum chloride is this. AlCl3 + 3 NH4OH equals 3 NH4Cl + Al(OH)3.
Balance Cu2(SO4) plus Al yields Al2(SO4)3 plus Cu
2 Al+3 CuSO4 = Al2(SO4)3 + 3 Cu
You need 4Al and 3O2 This will give you 2 Al2O3
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3