To make a load calculation, you'd need the voltage (volts) and the current (amps) in the distribution line. That would give you the power consumption (watts), and you could find that by multiplying volts times amps. P = I x E [Power equals current times voltage.]
On new installations, load calculations are based on square footage of the building. The second calculation is based on the type of equipment that is to be connected. If you want to measure the load on an existing breaker box, find the current draw coming into the box times the highest voltage coming into the breaker box and multiply them together for the total wattage of the breaker box at that moment in time.
Any continuous load shouldn't exceed the rated kV.A or your generator.
what is a circuit breaker / fuse current rate value for lamp and fan load circuit
Need to know what the wattage or the amperage is of the appliance. The load amperage is what governs the wire size and the breaker to protect the circuit.
No, add new breaker,find a junction box and split the series, or add a box and split the load. You only need to do this if the breaker is tripping from overload. 12ga wire should have a 20amp breaker not a 15amp. If I understand your question,wired in parallel, this would be one hot connected to two breakers, first off two breakers is 220v not 120v , and 220v has two hot wires. Never connect two breakers together on one line.
For a continuous load the circuit breaker is set 25% higher than the load current. So a 20-amp breaker is used with a continuous 16-amp load.
A breaker is based on the amperage that is drawn by the pump motor load. Find the full load amperage of the motor. The wire fed from the breaker has to be rated at 125% of the motors full load amperage. The breaker for motors have to be over sized, usually 250% of the motors full load amps.
If you have contineous tripping on a breaker then there is a fault on the load of that breaker. Don't reset it any more. What is the breaker connected to?
what is a circuit breaker / fuse current rate value for lamp and fan load circuit
what is a circuit breaker / fuse current rate value for lamp and fan load circuit
The first thing you have to do is find the full load amps of the motor. The wire size feeding the motor has to be 125% of the full load current. The breaker is usually 250% of the full load current. If the voltage and amperage had been added to the question the exact breaker size could have been calculated.
Need to know what the wattage or the amperage is of the appliance. The load amperage is what governs the wire size and the breaker to protect the circuit.
Depends entirely on the load. (ie What's connected to it)
The load conductor is connected to the load side of the generator breaker. Once the generator is up to speed the load breaker is closed and the voltage is then applied to the load.
No, add new breaker,find a junction box and split the series, or add a box and split the load. You only need to do this if the breaker is tripping from overload. 12ga wire should have a 20amp breaker not a 15amp. If I understand your question,wired in parallel, this would be one hot connected to two breakers, first off two breakers is 220v not 120v , and 220v has two hot wires. Never connect two breakers together on one line.
For a continuous load the circuit breaker is set 25% higher than the load current. So a 20-amp breaker is used with a continuous 16-amp load.
A breaker is based on the amperage that is drawn by the pump motor load. Find the full load amperage of the motor. The wire fed from the breaker has to be rated at 125% of the motors full load amperage. The breaker for motors have to be over sized, usually 250% of the motors full load amps.
In the breaker box
yes. But this is not a handyman level project. It is suggested you "Call a pro." What you're looking for is not another "main breaker" but a "sub-panel" that is fed by a "feeder" cable from the main panel. Have your electrician calculate the load you'll need in the out-building, then design and install a new feeder circuit and sub-panel for it.