Each second has 1,000 msec in it.
Multiply the number of seconds by 1,000 and you have
the number of milliseconds in the same length of time.
ms or msec
MPH = miles per hour. In order to calculate hours from seconds, you just need to know that there are 3,600 seconds in an hour.
convert the time
To calculate the number of seconds in a day, you multiply the number of hours in a day (24) by the number of minutes in an hour (60) and then by the number of seconds in a minute (60). So, there are 24 * 60 * 60 = 86,400 seconds in a day.
To calculate how many seconds in 24 hours, multiply the number of hours by 60 and multiply that number again by 60.
1000 msec = 1 sec 30,000 msec = 30 sec
3500 msec
1000
ms or msec
MPH = miles per hour. In order to calculate hours from seconds, you just need to know that there are 3,600 seconds in an hour.
Let t=0 denote the start of transmission. At t=1 msec, the first frame has been fully transmitted. At t=271 msec, the first frame has fully arrived. At t=272 msec, the frame acknowledging the first one has been fully sent. At t=542 msec, the acknowledementbearing frame has fully arrived. Thus, the cycle is 542 msec. A total of k frames are sent in 542 msec, for an efficiency of k/542. Hence a) k=1, efficiency=1/542=0,18% b) k=7, efficiency=7/542=1,29% c) k=4, efficiency=4/542=0,74%
250 msec
Multiply by 24x60x60. This is 86400 seconds in a day.
www.msbshse.ac.in ORwww.mah.nic.in/msec
around 4 msec
Generally about 300 msec.
Let t=0 denote the start of transmission.At t=1 msec,the first frame has been fullytransmitted.At t=271 msec,the first frame has fully arrived.At t=272 msec,the frameacknowledging the first one has been fully sent.At t=542 msec,the acknowledgement-bearingframe has fully arrived.Thus, the cycle is 542 msec.A total of k frames are sent in 542 msec,for anefficiency of k/542.Hence(a)k=1,efficiency=1/542=0.18%(b)k=7,efficiency=7/542=1.29%(c)k=4,efficiency=4/542=0.74%