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Number of atom per unit cell in the Bcc crystal structure is?
2
A compound having Bcc geometry has atomic mass 50 What is the density of the unit cell if its edge length is 290 pm?
Length of the edge , a = 290 pm =290 x 10-10 cm Volume of unit cell = ( 290 x 10-10 cm )3 = 24.39 x 10-24 cm3 Since it is bcc arrangement, Number of atoms in the unit cell, Z = 2 Atomic mass of the element = 50 Mass of the atom = atomic mass/ Avogadro number = M/No = 50/6.02 x 1023 Mass of the unit cell = Z x M/No = 2 x 50/6.02 x 1023 = 100/6.23 x 1023 Therefore , density = mass of unit cell / volume of unit cell = 100/6.023 x 1023 x 24.39 x 10-24 = 6.81 g cm-3
Why do Non-metal atoms gain electrons to become an ion?
bcc it's the same
What are the three differences packing arrangements found in metallic crystals?
Most metals and alloys crystallize in one of three very common structures: body-centered cubic (bcc), Li is an example of bcc , hexagonal close packed (hcp) Au is an example of hcp, or cubic close packed (ccp, also called face centered cubic, fcc) Ag is an example of fcg. The yield strength of a "perfect" single crystal of pure Al is ca. 10^6 psi.
Which bacteria grow in the betadine?
Burkholderia cepacia complex (BCC) is a group of catalase-producing, lactose-nonfermenting, Gram-negative bacteria composed of at least 17 different species, including B. cepacia, B. multivorans, B. cenocepacia, B. vietnamiensis, B. stabilis, B. ambifaria, B. dolosa, B. anthina, and B. pyrrocinia.B. cepacia is an important human pathogen which most often causes pneumonia in immunocompromised individuals with underlying lung disease (such as cystic fibrosis or chronic granulomatous disease).It also attacks young onion and tobacco plants, as well as displaying a remarkable ability to digest oil. Pathogenesis BCC organisms are typically found in water and soil and can survive for prolonged periods in moist environments. Person-to-person spread has been documented; as a result, many hospitals, clinics, and camps have enacted strict isolation precautions for those infected with BCC. Infected individuals are often treated in a separate area from uninfected patients to limit spread, since BCC infection can lead to a rapid decline in lung function and result in death.
Number of atom per unit cell in the Bcc crystal structure is?
2
How do you calculate density of compounds?
p = n x Mr / Vc x NAwhere n is the atoms/unit cell e.g. fcc packing n = 4 and for bcc packing n = 2Mr is the Atomic Mass in g/molVc is the volume/unit cell cm3 = a3 where a can be found by the radius of the atom and the packing used. e.g in bcc packing it is "a = 4r/1.732" . In Fcc packing it is "a= sin (4r)" or "a = cos (4r)"NA is avorgados constant, = 6.023 x1023
Show that the atomic packing factor for the Bcc crystal structure is 0.68?
In body-centred cubic structure,The no. of atoms per unit cell= 2Volume of 2 atoms (spherical)=2*(4/3)πr3We know the radius of atom in BCC isr = a√34Volume occupied by the atoms per unit cell(v) = 8πa√33 4v == 8πa33√3------- ---------3 4*4*4Volume occupied by the atoms per unit cell(v) =πa3√3----8Volume of the unit cell for a cubic system(V) = a3Atomic packing factor (APF) =(πa3√3/8)--------------a3√3(or) APF =π---------8APF = 0.68Therefore, we can say that 68% volume of the unit cell of BCC is occupied by atoms and remaining 32%volume is vacant.Thus the packing density is 68%.
How do you calculate theoretical density of compound?
p = n x Mr / Vc x NAwhere n is the atoms/unit cell e.g. fcc packing n = 4 and for bcc packing n = 2Mr is the atomic mass in g/molVc is the volume/unit cell cm3 = a3 where a can be found by the radius of the atom and the packing used. e.g in bcc packing it is "a = 4r/1.732" . In Fcc packing it is "a= sin (4r)" or "a = cos (4r)"NA is avorgados constant, = 6.023 x1023
A compound having Bcc geometry has atomic mass 50 What is the density of the unit cell if its edge length is 290 pm?
Length of the edge , a = 290 pm =290 x 10-10 cm Volume of unit cell = ( 290 x 10-10 cm )3 = 24.39 x 10-24 cm3 Since it is bcc arrangement, Number of atoms in the unit cell, Z = 2 Atomic mass of the element = 50 Mass of the atom = atomic mass/ Avogadro number = M/No = 50/6.02 x 1023 Mass of the unit cell = Z x M/No = 2 x 50/6.02 x 1023 = 100/6.23 x 1023 Therefore , density = mass of unit cell / volume of unit cell = 100/6.023 x 1023 x 24.39 x 10-24 = 6.81 g cm-3
What is the most malignant of skin cancers?
Basal cell carcinoma (BCC)
In Psychology what does Bcc mean?
The only listed medical meaning for the abbreviation of BCC is basal cell carcinoma. The other listed meaning for this abbreviation is blind carbon copy.
How do you use Bcc in a medical sentence?
The pathology report confirmed basal cell carcinoma.
Vanadium at 20c is Bcc and has an atomic radius of 0.143 nm calculate a value of its lattice constant a in nanometers?
For all BCC lattice structures, the Lattice constant (a) can be found by : a = (4r) / sqrt(3)
What is primitive and non primitive cell?
Primitive unit cells use every lattice point as a unit cell vertex.Non-primitive unit cells, however, contain extra lattice points not at the corners.
Does bcc is aware of bcc recipients?
No.
What does the medical abbreviation Bcc mean?
BCC can stand for basal cell carcinoma. In the old schema for reporting pap smear results it stood for benign cellular changes. It can also mean blind carbon copy.
