There is not enough information to answer the question. You need to know the distances between the centres of mass of the plumb bob and the two large masses. The plumb bob may be treated as a point particle, and the distance to the centre of the earth can be approximated by the average radius, but that still leaves the distance to the centre of the mountain.
Assuming the mass and density is known, divide the mass by the density.
2.9 kg
If you know the temperature, pressure and volume of the vessel, you can calculate the amount of moles through the Ideal gas law. PV = nRT That is assuming you have ideal conditions. If not, a variance of the ideal gas law can be used in order to get the moles of your gas.
Assuming the speed of light in air is already known (it is close to the speed of light in a vacuum), you might check how the light refracts when it changes from air to water (at what angle), and then use Snell's Law.
I guess you mean the centripetal acceleration in its orbit around the Sun. That's not something that will usually be found in references such as the Wikipedia, but you can calculate it in several ways. 1) Use the law of gravitation to calculate the force between an object of mass 1 kg. at Mercury's distance from the Sun, and the Sun. Any other mass will do as well, but after calculating the force, you need to calculate the acceleration, so the mass of Mercury (or another object at the same distance) cancels in the calculation. 2) Look up Mercury's orbital data. Assuming a circular orbit, calculate the centripetal acceleration as v2/r.
Effort(upwards) and Load(downwards) pivoting on Fulcrum. Assuming positive y axis is upwards and negative downwards.
They are the same, assuming the rain is falling directly downwards.
The problem with this question is that you did not provide any solutions, as stated, to calculate the freezing point for.
Assuming you know the circumference (C) it's... (C/Pi)/2.
Assuming you know the radius - the formula is Pi x Radius2
Assuming negligible air resistance, the acceleration of a projectile near the Earth's surface is always the gravitational 9.81 m/sec/sec downwards, regardless of where in the trajectory the projectile is.
Assuming no change in temperature and pressure, calculate the volume of O2 (in liters) required for the complete combustion of 14.9 L of butane (C4H10):
The electrodes will not pass a current unless there is a voltage applied between them. If a voltage source such as a battery or power supply is attached, then a current will flow and a meter will show a deflection. Water is not a good conductor of electricity. Pure, distilled water will pass a lower current than water that has impurities dissolved in it (assuming that other parts of the apparatus remain the same).
Assuming you can keep your feet on the ground, there should be no difference. Since the forces of gravity act vertically, they have no effect on things you're trying to do horizontally.
Assuming the room is rectangular, multiply length x width (both in feet).
Assuming the mass and density is known, divide the mass by the density.
The force of gravity is the same, whether the object doesn't move at all, whether it moves horizontally, vertically, diagonally, or whatever. The force is about 9.8 newton/kilogram.Therefore, if no other forces act on the object, it will accelerate downward at a rate of 9.8 meters/second squared - again, no matter how the object is moving at any given time. Under gravity (and assuming no other forces are significant - such as air resistance), an object that initially moves horizontally will have the tendency to move in a parabola.