The force required to lift a given mass perpendicularly to, just at, and at a constant velocity (including zero velocity) from, the Earth's surface may be determined from Newton's Second Law of Motion, F=MA, by substituting 'G', the acceleration of gravity, for A. So, F=MG Which essentially defines the distinction between mass and weight. I gave this definition because of the use of "vertical" in the question. As long as the "distance" is small compared to the radius of the Earth and the other conditions are met, the distance is irrelevant to the force required to lift the object. The distance does figure in the amount of "work" expended in lifting the object however, according to the relationship W=FD. If you are moving a mass on a ramp, under the effects of friction, under acceleration, or in any other way that doesn't meet the conditions described above, then the force calculated as shown will still apply, and must be added to the total force as a vector contribution. (The above applies to objects NOT moving at relativistic speeds, but if you are designing a particle accelerator you probably shouldn't be getting your advice from Wikianswers!)
Power = (work) divided by (time) If you don't know the amount of work, you can calculate it. Work = (force) times (distance).
-- Magnitude of the force (or force as a function of time) -- Distance through which it acted (or position as a function of time) -- Duration of the time during which it persisted Work is the product of (force) x (total distance). Power is (work) divided by (duration of the time). If the force and distance are functions of time, then I'm not sure how to do it right now, but I know there's an integral in there somewhere, and I'm not happy about that.
Multiply the quantities you know. Distance = (rate) x (time)
i dont know that's why I'm asking
Time equals distance divided by rate.
Power = (work) divided by (time) If you don't know the amount of work, you can calculate it. Work = (force) times (distance).
It depends on what else you know. If you know the mass and can measure the acceleration, you can use that to calculate force, but there are other ways to calculate force.
torque in * input rpm/output rpm = torque out
-- Magnitude of the force (or force as a function of time) -- Distance through which it acted (or position as a function of time) -- Duration of the time during which it persisted Work is the product of (force) x (total distance). Power is (work) divided by (duration of the time). If the force and distance are functions of time, then I'm not sure how to do it right now, but I know there's an integral in there somewhere, and I'm not happy about that.
Actual Mech. Advantage
Multiply the quantities you know. Distance = (rate) x (time)
If you know the amount of work, and distance, set up an algebraic expression. For instance if the amount of work is 40, and the distance is 2 feet, and you let F= effort force, the equation is 2F=40. You solve by dividing by both sides by 2. So, the effort force is 20.
i dont know that's why I'm asking
the area over which the force acts
To know the direction of the torque acting on the coil, whether the coil is vertical or horizontal, you will compare the direction of the magnetic force or its rotation to the direction of the coil. If the coil is vertical and the magnetic force is in the direction of the coil rotation, then the direction of the torque will be the same.
Applying a force through a distance is known as work. Work equals force in Newtons times distance in meters, and the unit for force is the Newton•meter, N•m.
THE BODY IS AT REST IN THE VERTICAL DIMENSION.