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How do you calculate the horse power required for 60 RPM and a 1.5 meter long shaft in 3.5 cubic meter volume tank?
Wiki User
∙ 16y ago
First, Torque = 1.5 meter x 3.5 (cubic meter)x 1000 (litres/cubic meter) x 1 (kg/litre) = 5250 kg. meter Horse Power = Torque x rpm / 5252 = 5250 x 60 /5252 = 59.97 First, Torque = 1.5 meter x 3.5 (cubic meter)x 1000 (litres/cubic meter) x 1 (kg/litre) = 5250 kg. meter Horse Power = Torque x rpm / 5252 = 5250 x 60 /5252 = 59.97
Wiki User
∙ 16y ago
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