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If you know the distance then you use the equation

d = x0 + v0t = 1/2 at2

if the object starts from rest then v0 = 0

If the object starts at zero distance the x0 = 0

d = 1/2 at2

Squareroot(2d/a) = t

Q: How do you calculate the time it takes an object to fall?

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d=displacement v=initial velocity t=time a=acceleration Our basic formula for displacement: d=vt+.5at2 becomes: t = (√(v2+2ad)-v)/a

That number is what we call the object's "speed".

Time equals distance divided by rate.

Use a stopwatch.

if an object is lightr it will fall slower because gravity wont take it down as fast if it is heavier it will make the gravity pull it down faster

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Galileo

Galileo galilei

Before you test it, you could state the hypothesis in two different ways You could say: "The mass of a falling object has no effect on the time it takes to fall some distance." Or you could say: "The time a falling object takes to fall some distance depends on its mass." You could use the same tests to investigate EITHER hypothesis. --------------------------- The mass of a falling object has no effect on the time it takes to fall some distance assuming zero air resistance.

The kinetic energy of a falling object is directly proportional to the distance it falls.But the distance is not directly proportional to the time in fall, so the KE is not directly proportionalto the time either.

If thrown horizontal from same height the faster object will travel farther horizontally, but time to fall is the same. If thrown straight up, the faster object will take longer to fall

how is the diameter related to the time it takes the ball to fall

Add the time it takes to get there to the time it takes to come back.

calculate the following time it takes to pump 40 gallons of gasoline

To determine the acceleration of an object, you must calculate its change in velocity per unit of time.

The higher the concentration of a fluid, the longer the time it takes for an object to fall and therefore the smaller the terminal velocity.

It depends on what object it is. You have to figure out it mass and such.

Distance over time.