5x+4y = -4
4y = -5x -4
y = -5/4x -1 or as y = -1.25x -1 both of which are in slope-intercept form
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
A quadratic equation.
2
Solving the equation for "y" gives you the slope-intercept form.
It is the general form of a quadratic equation.
y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
A quadratic equation.
2
Solving the equation for "y" gives you the slope-intercept form.
9
It is the general form of a quadratic equation.
It actually means "reacts to form".
x = 4.5
You have to solve the equation for "y", in other words, change it to a form where "y" is on the left, and everything else to the right. You will get an equation of type y = ax + b, where a is the slope, and b the y-intercept.
The equation contains variables which are only raised to the first power.