Construct the Lagrange interpolating polynomial
P1(x) for f(x) = cos(x)+sin(x) when
x0 = 0; x1 = 0:3. Find the absolute error on the interval [x0; x1].
Since secant theta is the same as 1 / cosine theta, the answer is any values for which cosine theta is zero, for example, pi/2.
Before calculators, trig functions in general were evaluated using a slide rule (fast, but accurate to only 2-3 significant digits, and interpolation tables, which required interpolating between values in a printed table of function values to get up to 3-4 significant digits. Tricks were a big part of the repertoire - for example for small angles of less than about 7 degrees, sin and tangent are equal to the angle in radians. Spherical geometry was fairly labor intensive, to say the least, since several trig functions are used for even simple distance and angle calculations. Special tables were printed for common cases, such as plotting great circle distances and bearings for terrestrial navigation. In a desert island setting, given infinite time and desire, trig functions can be calculated using various converging series, with the Taylor series being a commonly taught (though slow!) example.
Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.
The amplitude of a sine (or cosine) curve is the difference between the maximum and minimum values of the curve, measured over a whole cycle.
That's the definition of trigonometry. Triangles are completely dependent upon their side lengths, and can be defined by only three values.
Substitute that value of the variable and evaluate the polynomial.
false
Find values of the variable for which the value of the polynomial is zero.
Interpolation in general is a way to determine intermediate values from a set of coordinates. Linear interpolation would be to fit a single linear function to the entire set of coordinates. Piecewise linear interpolation would then be to determine intermediate values from the set of coordinates by fitting linear functions between each set of coordinates. Connect-the-dots so to speak.
interpolation
Interpolation.
Interpolation
Both, interpolation and extrapolation are used to predict, or estimate, the value of one variable when the value (or values) of other variable (or variables) is known. This is done by extending evaluating the underlying function. For interpolation, the point in question is within the domain of the observed values (there are observations for greater and for smaller values of the variables) wheres for extrapolation the point in question is outside the domain.
The graph of a polynomial in X crosses the X-axis at x-intercepts known as the roots of the polynomial, the values of x that solve the equation.(polynomial in X) = 0 or otherwise y=0
extreme
A local minimum.
2 or 5