11 degrees C = 51.8 degrees F
The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C
Use this formula to convert degrees Fahrenheit (F) to degrees Celsius (C): (F - 32) / 1.8 = C
90 degrees F
33 °c = 91.4 °f
Type in google "convert 20 degrees c to f" and you get 68oF
You can use this equation to convert degrees Celsius (C) to degrees Fahrenheit (F): (C x 1.8) + 32 = F
11 degrees C = 51.8 degrees F
The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C
Use this formula to convert degrees Fahrenheit (F) to degrees Celsius (C): [°C] = ([°F] − 32) × 5⁄9
F=(9/5)C+32 (9/5)(20)+32=68 so 20 degrees Celsius is equal to 68 degrees Fahrenheit.
Use this formula to convert degrees Fahrenheit (F) to degrees Celsius (C): (F - 32) / 1.8 = C
90 degrees F
The formula for this conversion is C=(F-2)x5/9. The answer is that 20 degrees F= 10 degrees C.The Formula is C=(F-32)*5/9 so 20 F is actually -6.6667 CThe first formula is wrong because the freezing point of water is 32 F or 0 C, so if 20 Fahrenheit is below the freezing point, how can it be converted to above the freezing point in Celsius?
Use this formula to convert degrees Fahrenheit (F) to degrees Celsius (C): (F - 32) / 1.8 = C
-4 deg C = 24.8 deg F
- 20 °C is equal to -4 °F To convert C to F, you use this formula, 1.8*C + 32 = F So if C = -20, we have, 1.8*(-20) + 32 = F (-36) + 32 = F (-4) = F -4 -40 Celsius is -40 F. The formula is 9./5 C + 32=F