Study guides

Q: Can you write the square root of 98 as 6 times the square root of 3?

Write your answer...

Submit

Related questions

98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.

9.899494936611665It is: 7 times square root of 2Â± 9.899495

It is 7 times the square root of 2

No. If the square root of 98 was an integer, 98 would be a perfect square.

The square root of 9604 is 98.

√98 ~= 9.899

The simplified square root of 98 is: ±9.9 or ±10

49

49

Expressed as a surd, sqrt(98) + sqrt(2) = 8 sqrt(2).

2.83 to the nearest hundredth.

It is 98 because 98*98 = 9604

sq. root of 98 =sq. root of 49*2 =7*sq.root of 2 =7*1.414 =9.898

98

The square root of 9604 = 98. (98 x 98 = 9604)

no it is irrational

it would be 32.2

rational

9.9

7√2

-10 and +10.

It is an irrational number

√98 = 7√2 = 9.9

It becomes an irrational number which can't be expressed as a fraction

7square roots of 2