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Q: How do you decide if a two-digit number is a multiple of a one-digit number?

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If he number has a multiple other than itself it is composite.

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

It is even if it is a multiple of 2 Or it will divide by 2 with no remainder

Divide the 2-digit number by the 1-digit number. If the quotient comes out a whole number, then the big one is a multiple of the small one.

#include <stdio.h> int main(void){ // Local Declerations int intNum; int midDigit; // Statements printf("Enter a 5 digit integral number: "); scanf("%d", &intNum); //the assignment expression below is used to calculate the mid digit oneDigit = (intNum % 1000) / 100; printf("\nThe middle digit is: %d", oneDigit); return 0; }

Any number that is not a multiple of 7.Any number that is not a multiple of 7.Any number that is not a multiple of 7.Any number that is not a multiple of 7.

An even number can be a multiple of an odd number OR an even number. An odd number cannot be a multiple of an even number.

If one number is a multiple of the other, the number that is the multiple is the LCM.

A multiple of any number would be the product of that number and any other nonzero whole number. A multiple of 4 is 8. A multiple of 100 is 300.

The number 58 is not considered a multiple of 4. A simple way of figuring out if a number is a multiple of another number is by dividing the number in question by the multiple. Such as finding out that 12 is a multiple of four. 12/4=3. If the number comes up as a whole number - then that number is a multiple.

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