How do you differentiate 2tanx?

Answer 1

Coefficients can be removed when differentiating, i.e. d/dx 2tanx = 2 d/dx tanx

You should know that d/dx tanx = sec2x (either by differentiating sinx/cosx or by just remembering the derivatives of common trig functions, as it will come in handy).

So the answer is 2sec2x

Answer 2

For a number in form af(x) while differentiating with dont interfere with the constant a.

So, it is a d(f(x))/dx

Here assuming were differentiating with respect to x,

we have 2*d(tan x)/dx

From here you have options weather you can differentiate ie based on uv or u/v method. I'll be using u/v (easy to apply for division),

Here's the general form,

(u/v)' = {vu' - uv'}/v^2

d(tan x)/dx =d(sinx/cosx )/dx = {cosx(sinx)' - sinx(cosx)'}/(cos^2)

= {(cos^2 x) - (-sin^2x)}/cos^2 = {(cos^2 x) +(sin^2x)}/cos^2

Since sin^2 x + cos^2 x =1 ,

we have

d(tan x)/dx = 1/cos^2x = sec ^2 x.

Therefore the final answer for,

2d(tan x)/dx = 2sec^2 x

Answer 3

2000 points

Answer 4

dat

Answer 5

Ur answers are too hard