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In general, you cannot.

If, in the unlikely event that it is a regular nonagon, you draw the perpendicular bisectors of any two sides. they will intersect at the centre. Join each of the vertices to the centre and you have the required division.

This will not work for non-regular nonagons, which are the majority.

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βˆ™ 10y ago
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Q: How do you divide a nonagon into ninths?
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