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If you have six boxes, with an odd number of coins in each box, in total you would have an EVEN number of coins. Therefore, this isn't possible. (odd + odd = even, odd + odd + odd = odd, etc. - if you add an even set of odd numbers, the total will always be even.)

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Q: How do you divide fifteencoins into six box such that each box contains odd no of coins?
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