This is done by using a method called the distributive property. This is actually quite simple if we had x(y+z) we would distribute that xx, and get xy+xz. This is what we will use to solve this problem.
If we take 6(5-2x) -4(3x+1) I have made the + sign bold, assuming that this is the symbol there.
So next we'd use the distributive property and get 30-12x-12x-4.
Now we would combine like terms, and get 26-24x.
For x-2x= 3x-43x+1 x-2x= -x and 3x-43x+1 = -40x+1 so -x= -40x+1 subtract -x from both sides 0= -39x +1 -1 = -39x so 1=39x so x=1/39
9194 It may not be right but this is what i come up with
In the equation 43X +2=5X, X=-1/19.
43x+35 (given the question doesn't define what x is)
3x - 4 = 83x = 8+43x = 12x = 12/3 = 4
For x-2x= 3x-43x+1 x-2x= -x and 3x-43x+1 = -40x+1 so -x= -40x+1 subtract -x from both sides 0= -39x +1 -1 = -39x so 1=39x so x=1/39
If you mean 3x - 2x * 3x * 43x - 2x * 3x * 43x - 5x * 43x - 20x-17x (negative 17x) is your answer
9194 It may not be right but this is what i come up with
the answer we are all looking for is 645!
In the equation 43X +2=5X, X=-1/19.
The enesis is abiological when the abiosis is in the abiotrophy into the abirritate crossing the fuel pump's abju. In other words, (x + 1)^10 = x^10 + 10x^9 + 43x^8 + 118x^7 + 210x^6 + 252x^5 + 210x^4 + 118x^3 + 43x^2
43x+35 (given the question doesn't define what x is)
The Power
4300x
It means the zoom power, i.e. how much magnification is possible at the long end of the zoom.
what magnification is ontained with the high power objective
sqrt( 3x + 4 ) = 23x + 4 = 43x = 0x = 0Marvelous.