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To the nearest ten, 30 cm
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∙ 7y ago
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What does 315 estimate to?
To the nearest ten, 320
What is a estimate of 41cm?
To the nearest ten, 40 cm
What is the estimate of 180?
The answer depends on what you wish to do with the estimate. If you wanted to divide by 25, I would suggest 175 since 175/25 = 7. If you wanted to add 315 then I would suggest 185 since 185 + 315 = 100 + 85 + 15 + 300 = 100 + 100 + 300 = 500.
What number can be decomposed into 3x3x5x7?
315
What number represents 315 percent?
315% = 31,500
If you have 315 feet how many centimeters do you have?
Since there are 30.48 cm per foot, just multiply 315 by 30.48:315 feet x 30.48 cm = 9,601.2 cm
Convert 315 cm in to m?
3.15m
How many mm is 315 cm?
To help you get started, 1 cm = 10 mm...
What is the estimate of 315 divided by 8?
39.375
What does 315 estimate to?
To the nearest ten, 320
How many inches in 800 CM?
Approximately 315 inches.
How big is 315 cm in inches?
The answer is 124.02 inches (approx.). Inches and centimeters are both units of linear measurement. Inches are used in the imperial system whereas centimeters are used in the metric system. To convert from cm to inches, multiply the cm unit by 0.393701.
What is the most reasonable estimate for 315 divide by 4?
78.75
What is a estimate of 41cm?
To the nearest ten, 40 cm
What is the estimate length of a pen in centimeters?
I estimate 15 cm.
How many centimeters are in 315mm?
There are 25.4 millimetres in one inch. Therefore, rounded to two decimal places, 315 millimetres is equal to 315/25.4 = 12.40 inches.
What are the diagonal lengths of an isosceles trapezoid whose longest parallel side is 25 cm with a height of 18 cm and an area of 315 square cm showing all work leading to the answer?
Let the other parallel side be x and then use Pythagoras to find diagonal lengths: Area: 0.5*(25+x)*18 = 315 sq cm Other parallel side: x = (315*2)/18 -25 = 10 cm Two right angle triangles can be formed with bases of 17.5 and heights of 18 cm Using Pythagoras: 17.5square+18squared = 630.25 and its sq rt is 25 to nearest integer Therefore the diagonal lengths are: 25 cm to the nearest whole number
