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Q: How do you factor -11y plus y2 plus 30?

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This is not factor-able.

25x2 - 10xy + y2 = (5x - y)2

(y + 7)(y + 7)

(y + 5) (y + 2)

Using real numbers, you cannot.

(y+2)(y+3)

(y + 30)(y - 1)

y2 + y2 = 2y2

(x - y + 7)(x + y)

(3x - y)(3x - y)

(x2 - xy + y2)(x + y)

(y - 8)(y - 2)

(y-12)(y-2)

(y + 5)(y - 4)

(y - 1)(y - 4)

x2 -y2 +4y-4=(x+y)(x-y)+4y-4

(y + 3)(y - 10)

I feel like there is something wrong with your question because subtracting y2 on both sides leaves you with 8y=0; then, y=0

It goes to (x-5)(x-3)

(y + 8)(y - 2)

(2 pi) x sqrt(30)

It is: y2

y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4

30

y2=-x2-8x+6