That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-1 plus or minus one third itimes the square root of 7) divided by 4.
x = -0.25 + 0.22047927592204922i
x = -0.25 - 0.22047927592204922i
where i is the square root of negative one.
9x2 - 18x + 99(x2 - 2x + 1)==========
(x + 2)(3x - 1)(3x + 1)
If that's + 18x + 1, the answer is (9x + 1)(9x + 1) or (9x + 1)2
9x(x2+3x-10)
Type your answer here... 81
(9x - 1)(9x - 1)
(x+1)(x+8)
3(x2 + 3x + 1)
9x2 + 8x - 1 = (9x - 1)(x + 1)
x4 + 2x3 - 9x2 + 18x = x(x3 + 2x2 - 9x + 18) which I do not think can be factorised further.
(3x - y+ 2)(3x + y + 2)
(9x)2 +9x/(45x)2 +81= 9+9x/86