Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
2a
4(4a2 - b2) 4(2a + b)(2a - b)
The GCF is 4a. The equation factors into 4a(5a + 9)
(4a - 1)(a - 4)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a3 - 4a2 = 4a2*(a - 1)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
It is 4a2.
x2=(4a)(a) x=√4a2 x=2a The geometric mean of a and 4a is 2a
= 4a2 + 2ab 2b2
(2a + 5)(2a - 5)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
(2a + 1)(2a - 5)
2a
There are two answers in the solution set. To solve this we factor the left side to become 4a(a-4). This lets us get the 4. The other answers is 0. Set 4a=0 and solve for "a" and then a-4=0 and solve for "a."