(a + 2 - b) (a + 2 + b)
(b + 8)(b - 1)
4aa-bb fits the special type of polynomial in the form of x**2-y**2 which can be rewritten as (x-y)(x+y) sqrt(4aa) = 2a sqrt(bb) = b (2a-b)(2a+b)
(a + b)2 - 100 = (a + b + 10)(a + b - 10).
4a² - b² = (2a + b)(2a - b)
6(b - ac + b2 - bc)
No, unless "a" happens to be equal to 0, or to 1.
(2b - 5)(b + 7)
All the time
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
Same as (A-B)x(A+B)
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
n(2a - b)(2a + b)(4a^2 - 2ab + b^2)(4a^2 + 2ab + b^2)
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).
-1ab^2 + 5b + 8 Step-by-step explanation: 3a^2+9ab+5-4a^2-4ab+3 3a^2-4ab^2=-1ab^2 9ab-4ab=5ab 5+3=8 -1ab^2+5ab+8
3a squared b squared
(a+b)(a squared-ab+b squared)
It is: (B -10)(B +10) when factored
(a - b + 2)(a + b + 2)