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Q: How do you factor 4x squared minus 1?

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(2x - 1)(4x + 1)

(2x-1)(2x-1) = 4x^2 -4x + 1

8X^2 - 4X^2 factor out a 4X^2 4X^2(4 - 1) all I can see to do

2x(2x - 1)

(4x - 1)(x - 5)

(4x - 3)(x - 1)

There is no rational factorisation.

4(x - 1)(x + 1)

(2x - 1)(2x + 5)

8x2-10x-3 = (2x-3)(4x+1) when factored

4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)

Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5

It is (A-1)(A+1) when factored

8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)

(4x - 1)(4x + 1)

X2 - 4X - 5 = 0 easy factor, what two factors of - 5 add up to - 4 (X + 1)(X - 5) X = - 1 ------------- X = 5 --------------

OK. 4x2 + 4x + 1 = (2x + 1)2

4x(4x^2 + 3x + 1)

2(x - 1)(2x + y)

(x + 1)(x - 8)

(x - 1)(x + 1)

20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)

sqrt(4x+7) -4 = sqrt(4x-1) squared : (sqrt(4x+7) -4)2 = 4x-1 (4x+7) - 2x4xsqrt(4x+7) +16 = 4x-1 -8xsqrt(4x+7) = -24 sqrt(4x+7) = -24/-8 = 3 squared : 4x+7 = 32 = 9 4x = 9-7 = 2 then x=1/2

2x squared - 5x - 3 = (2x +1)(x -3)

3x(6x - 1)