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If that's + 2y, the answer is (y + 4)(y - 2)

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12y ago
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11y ago

I feel like there is something wrong with your question because subtracting y2 on both sides leaves you with 8y=0; then, y=0

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11y ago

8y2-10y-3

8y2-12y+2y-3

4y(2y-3)+1(2y-3)

(4y+1)(2y-3)

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13y ago

4(2y-3)

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Q: How do you factor y2 2y-8?
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Factor the expression y4-256?

y4 - 256 = (y2 - 16)(y2 + 16) = (y - 4)(y + 4)(y2 + 16)


How do you factor x2-y2?

x2-y2=(x-y)(x+y) which is a well known identity.


What are the factor pairs for Y2 - 7Y - 30?

(y + 3)(y - 10)


What is the factor of y-2y-15?

If that's y2, the answer is (y - 5)(y + 3)


How do you factor 3x3-81?

9y-81=9*(y-9)