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(x - y)(x + y)
Wiki User
∙ 8y ago
Wiki User
∙ 12y ago(x2 - y2) = (x + y) (x - y)
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How do you factor completely x to the fourth power minus x squared minus 2?
(x2 + 1)(x2 - 2)
How would you factor x4-2?
(x squared plus the square root of 2) times (x squared minus the square root of 2).
How do you you factor 3x squared minus 25x minus 28?
3x squared minus 25x minus 28
How do you factor the expression two m squared minus eight?
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
How do t factor 25a squared minus 16?
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
How do you factor x squared minus four y squared minus twenty eight?
There are no rational factors.
How do you factor perfect square binomial?
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
What is the square root of 28 minus the squared root of 7?
The square root of 28 minus the squared root of 7 =±2.64575131
How do you factor this polynomial completely four x squared plus four x minus three?
(2x - 1)(2x + 3)
How do you factor 2q squared minus 10?
2(q^2 - 5) or 2(q - the square root of 5)(q + the square root of 5)
How do you factor a squared minus 9?
(a + 3)(a - 3)
How do you factor x squared minus 2x plus 2?
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 1 plus or minus i where i is the square root of negative one.
