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x3 - 4x2 + x + 6

The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor.

So

x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6

= x2(x + 1) - 5x(x + 1) + 6(x + 1)

= (x + 1)(x2 - 5x + 6)

= (x + 1)(x - 2)(x - 3)

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12y ago
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8y ago

(x + 1)(x - 2)(x - 3)

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Q: How do you factor x cubed minus four x squared plus x plus 6?
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