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Q: How do you factor x squared -12x plus 32?

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x2 + 12x + 32 = (x + 8)(x + 4)

x2 + 12x + 32 = (x + 4)(x + 8)

(x + 4)(x + 8)

x2 + 12x + 32 = x2 + 8x + 4x + 32 = x*(x + 8) + 4*(x + 8) = (x + 8)*(x + 4)

(b + 8)(b + 4)

(x + 8)(x + 4)

(x + 8)(x + 4)

No.

No.

It is: (c-4)(c-8) when factored

-2x2+32 -2(x2-16) -2(x+4)(x-4)

Yes.

OK, SO 4x = 12x + 32.SO 4x -12x-12x-12x+32 (subtract 12x from each side to get x on one side)SO -8x = 32 (simplify)SO -1 (-8x) = 32 (-1) (multiply each side by -1)SO 8x -32 (simplify)SO 8x / 8 = -32/8 (divide each side by eight (8) to get ""X"" by itself)SO x= -4SO x = -4.Does that help?Hope that helps!

If you mean -(x^2) - 4x + 32, then a simple way to do this is to factor out -1 first: -((x^2) + 4x - 32). Then you need simply to factorise the part inside the brackets

6y = 12x+32 Divide all terms by 6: y = 2x+5 and 1/3 which is now in slope intercept form

5x+32+7x+8=180. By the laws of commutativity we can thus say that 12x+40=180. Subtracting 40 we get 12x=140. Divide by 12 and you get x=(do it yourself) This has nothing to do with calculus by the way.

32 is 9, + 2 is 11

16 is an even, square, two-digit factor of 32.

x2 - 12x + 32 = 0 x2 - 8x - 4x +32 = 0 x(x -8) - 4(x -8) = 0 (x - 4)(x - 8) = 0 x = 4 or x = 8

2752 = 75625 42 = 16 32 = 9 22 = 4 75625/16 + 9 + 2 = 4737.5625

Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)

32 squared is 32 x 32 or 1,024.

(x - 8)(3x + 4)

4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x

5.6568542494923801952067548968388 squared = 32

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